Two data sets:



The camera integrates light across the TRITC passband, not at a single wavelength. The effective transmittance is the filter-weighted average of the BPB transmittance:
$$T_\text{eff} = \frac{\int S(\lambda)\,10^{-A(\lambda)}\,d\lambda}{\int S(\lambda)\,d\lambda}$$where $S(\lambda)$ is the TRITC transmitted intensity and $A(\lambda)$ is the BPB absorbance at the Nanodrop path length $l_\text{ref} = 0.1\,\text{mm}$. Applying Beer–Lambert gives the effective $(\varepsilon c)$ product:
$$A_\text{eff} = -\log_{10}(T_\text{eff}) = (\varepsilon c)_\text{eff}\,l_\text{ref} \quad\Rightarrow\quad (\varepsilon c)_\text{eff} = \frac{A_\text{eff}}{l_\text{ref}}$$This value applies directly to the stepped-height channel measurements because the camera sees the same filter-weighted signal.
| Quantity | Value |
|---|---|
| Wavelength overlap | 220–748 nm |
| Teff | 0.26916 |
| Aeff (at l = 0.1 mm) | 0.56999 AU |
| (ϵc)eff | 5.6999 AU/mm |
